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Old 02-13-2005, 09:56 PM   #13
DJ Ryan
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When you do the PNI chart you get two possible solutions:
P N I
0 3 0
0 1 2

Since 2i Is a root, and there can never be just ONE imaginary root, but like Kat said, -2i is your other root.

Multiplying (X-2i)(X+2i) gets you X^2+4

But usually you'll get planned problems which will come out with sensible roots, and by sensible I mean solvable because 95% of math past Algebra I is unneeded crap.
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