When you do the PNI chart you get two possible solutions: P N I 0 3 0 0 1 2 Since 2i Is a root, and there can never be just ONE imaginary root, but like Kat said, -2i is your other root. Multiplying (X-2i)(X+2i) gets you X^2+4 But usually you'll get planned problems which will come out with sensible roots, and by sensible I mean solvable because 95% of math past Algebra I is unneeded crap. |